1250. Longest Common Subsequence
2026/1/12大约 1 分钟约 373 字
1250. Longest Common Subsequence
难度: Medium
题目描述
Given two strings text1 and text2, return the length of their longest common subsequence. If there is no common subsequence, return 0.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
- For example,
"ace"is a subsequence of"abcde".
A common subsequence of two strings is a subsequence that is common to both strings.
Example 1:
Input: text1 = "abcde", text2 = "ace" Output: 3 Explanation: The longest common subsequence is "ace" and its length is 3.
Example 2:
Input: text1 = "abc", text2 = "abc" Output: 3 Explanation: The longest common subsequence is "abc" and its length is 3.
Example 3:
Input: text1 = "abc", text2 = "def" Output: 0 Explanation: There is no such common subsequence, so the result is 0.
Constraints:
1 <= text1.length, text2.length <= 1000text1andtext2consist of only lowercase English characters.
解题思路
代码实现
解决方案
java
class Solution {
public int longestCommonSubsequence(String text1, String text2) {
int n1 = text1.length();
int n2 = text2.length();
if (n1 == 0 || n2 == 0) {
return 0;
}
int[][] dp = new int[n1 + 1][n2 + 1];
for (int i = 0; i < n1; i++) {
for (int j = 0; j < n2; j++) {
if (text1.charAt(i) == text2.charAt(j)) {
dp[i + 1][j + 1] = dp[i][j] + 1;
} else {
dp[i + 1][j + 1] = Math.max(dp[i][j+1], dp[i+1][j]);
}
}
}
return dp[n1][n2];
}
}