199. Binary Tree Right Side View
2026/1/12大约 1 分钟约 391 字
199. Binary Tree Right Side View
难度: Medium
题目描述
Given the root of a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.
Example 1:
Input: root = [1,2,3,null,5,null,4]
Output: [1,3,4]
Explanation:

Example 2:
Input: root = [1,2,3,4,null,null,null,5]
Output: [1,3,4,5]
Explanation:

Example 3:
Input: root = [1,null,3]
Output: [1,3]
Example 4:
Input: root = []
Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 100]. -100 <= Node.val <= 100
解题思路
代码实现
解决方案
java
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> res = new LinkedList<>();
dfs(root,0,res);
return res;
}
private void dfs(TreeNode root,int depth,List<Integer> res){
if(root==null){
return;
}
if(depth==res.size()){
res.add(root.val);
}
dfs(root.right,depth+1,res);
dfs(root.left,depth+1,res);
}
}